Title: How to get child nodes (only folders and not leaf nodes) from easy ui tree Post by: Shalini on July 18, 2013, 09:09:18 PM Hi,
I need to get the child nodes from easy ui tree. And that child nodes should only include the sub folders and not the leaf nodes. I had achieved this with the below code. But this might have performance issue due to the for loop if i have a huge tree. Hence i would like to know if there is any other way where we can get only the sub folders. Please help me resolve this. Code: var node = $('#tt').tree('getSelected'); var child_node = $('#tt').tree('getChildren', node.target); // This gives all the childs i.e folders and leaf nodes. var count = 0; for(var i=0; i< child_node.length; i++) { var child = $('#tt').tree('isLeaf', child_node.target); //Boolean - true if the child_node is leaf, else false if(!child) count = count + 1; // Increment count and get the count of Folders when leaf is false } alert('count' + count); Regards, Shalini S. Title: Re: How to get child nodes (only folders and not leaf nodes) from easy ui tree Post by: stworthy on July 20, 2013, 06:53:53 AM A better solution is to extend a new method. The code below is the simple implementation of the 'getFolders' method.
Code: $.extend($.fn.tree.methods,{ To get the selected node's child folders, try this: Code: var node = $('#tt').tree('getSelected'); Title: Re: How to get child nodes (only folders and not leaf nodes) from easy ui tree Post by: Shalini on August 06, 2013, 02:50:38 AM Hi stworthy,
Thank you so much for your solution.. :) It works great. Regards, Shalini S. |