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Author Topic: keyboard navigation on Tree  (Read 7027 times)
korenanzo
Guest
« on: November 12, 2014, 05:09:37 AM »

Hi,

is it possible to navigate through the nodes of a tree by keyboard?

Thanks,
Ric
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stworthy
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Posts: 3581


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« Reply #1 on: November 12, 2014, 07:34:16 PM »

Please try to extend a method 'nav' to support the navigation on the tree.
Code:
$.extend($.fn.tree.methods, {
highlight: function(jq, target){
return jq.each(function(){
$(this).find('.tree-node-hover').removeClass('tree-node-hover');
$(target).addClass('tree-node-hover');
})
},
nav: function(jq){
return jq.each(function(){
var t = $(this);
t.attr('tabindex',0);
t.unbind('.tree').bind('keydown.tree', function(e){
var curr = getCurr();
if (!curr.length){return}
if (e.keyCode == 40){ // down
var li = getNext(curr);
if (li.length){
t.tree('highlight', li[0]);
}
} else if (e.keyCode == 38){ // up
var li = getPrev(curr);
if (li.length){
t.tree('highlight', li[0]);
}
} else if (e.keyCode == 13){
t.tree('select', curr[0]);
} else if (e.keyCode == 39){ // right
if (!t.tree('isLeaf', curr[0])){
t.tree('expand', curr[0]);
}
} else if (e.keyCode == 37){ // left
if (!t.tree('isLeaf', curr[0])){
t.tree('collapse', curr[0]);
}
}
e.preventDefault();
}).bind('mouseover.tree', function(e){
var node = $(e.target).closest('div.tree-node');
if (node.length){
t.find('.tree-node-hover').each(function(){
if (this != node[0]){
$(this).removeClass('tree-node-hover');
}
})
}
});
function getCurr(){
var n = t.find('.tree-node-hover');
if (!n.length){
n = t.find('.tree-node-selected');
}
return n;
}
function getNext(curr){
var n = $();
var node = t.tree('getNode', curr[0]);
if (t.tree('isLeaf', node.target)){
n = curr.parent().next().children('div.tree-node');
if (!n.length){
var p = t.tree('getParent', curr[0]);
if (p){
n = $(p.target).parent().next().children('div.tree-node');
}
}
} else {
if (node.state == 'closed'){
n = curr.parent().next().children('div.tree-node');
} else {
var cc = t.tree('getChildren', curr[0]);
if (cc.length){
n = $(cc[0].target);
}
}

}
return n;
}
function getPrev(curr){
var n = curr.parent().prev().children('div.tree-node');
if (n.length){
var node = t.tree('getNode', n[0]);
if (node.state == 'open'){
var cc = t.tree('getChildren', node.target);
if (cc.length){
n = $(cc[cc.length-1].target);
}
}
} else {
var p = t.tree('getParent', curr[0]);
if (p){
n = $(p.target);
}
}
return n;
}
})
}
})

Usage example:
Code:
$('#tt').tree('nav');
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aswzen
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aswzen
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« Reply #2 on: November 12, 2014, 08:19:41 PM »

thank you..but why this is not a default behaviour/features of a tree?
 Undecided
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Regards,
Sigit

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korenanzo
Guest
« Reply #3 on: November 13, 2014, 03:36:25 AM »

thanks,
RIc
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