hi, stworthy

sorry but is my first tree  

if the data were also:

<script>
    var data = [{
               id:100,
       text:'Node 1'
    },{
               id:200,
       text:'Node 2',
       children:[{
                            id:210,
          text:'Node 2.1'
       },{
                            id:220,
          text:'Node 2.2'
       },{
                            id:230,
          text:'Node 2.3'
       }]
    },{
               id:300,
       text:'Node 3'
    },{
               id:400,
       text:'Node 4'
    }];
</script>

then loadfilter:

loadFilter:function(nodes){
 return
}
how can I call for the ID node 200 and their children

thank for your time

awesome stworthy

 

Im very thankful

[-> Node 2--> Node 2.1--> Node 2.2--> Node 2.3]

according to this example

http://www.jeasyui.com/tutorial/tree/tree2.php

If I have this structure:

-> Node 1
-> Node 2
--> Node 2.1
--> Node 2.2
--> Node 2.3
-> Node 3
-> Node 4

How I can show only the node 2 and their children?

-> Node 2
--> Node 2.1
--> Node 2.2
--> Node 2.3

Following the demo I just get:

-> Node 2.1
-> Node 2.2
-> Node 2.3

I need to show Parent Node also

I saw this demo:

http://www.jeasyui.com/tutorial/datagrid/datagrid22.php

And what I need is show a tree instead the datagrid

that is possible??

Hi, sorry I was not doing the right tests.

No need to add anything, as this works ok

hi, Im using edatagrid extension to update some values

but not how to get server side some extra data

here my example:

Code:

$('#dg-ab').edatagrid({
	url: 'get_datagrid_data.php',
	idField: 'id_game',
	updateUrl: 'update_data.php',
});
<table id="dg-ab">
<thead>
<tr>
      <th field="game_name" width="290" sortable="true"></th>
      <th field="score_game" width="50" sortable="true">High Score</th>
      <th field="player1" width="50" sortable="true" editor="{type:'numberbox',options:{min:0, max:100, precision:2}}">Player 1</th>
      <th field="player2" width="50" sortable="true" editor="{type:'numberbox',options:{min:0, max:100, precision:2}}">Player 2</th>
      <th field="player3" width="50" sortable="true" editor="{type:'numberbox',options:{min:0, max:100, precision:2}}">Player 3</th>
      <th field="player4" width="50" sortable="true" editor="{type:'numberbox',options:{min:0, max:100, precision:2}}">Player 4</th>
      <th field="player5" width="50" sortable="true" editor="{type:'numberbox',options:{min:0, max:100, precision:2}}">Player 5</th>
</tr>
</thead>
</table>

the entire row was edited updating scores of five players per game
although not shown in Table I have the game id from the 'get_datagrid_data.php',
I need to get in 'update_data.php' is

$id_game = $_POST['id_game'];
$score_game = $_POST['score_game'];
$player_1_score = $_POST['player1'];
$player_2_score = $_POST['player2'];
$player_3_score = $_POST['player3'];
$player_4_score = $_POST['player4'];
$player_5_score = $_POST['player5'];

then the question is how to get the field score_game which is not editable?

hi thank you for your time

first change the name tag, like you said:

name="almacenes[]"

  I seems reasonable

but, then if I change this:

$almacenes = $_POST['almacenes'];

to this:

$almacenes = join(',', $_POST['almacenes']);

almacenes field is not saved in the database

mi query insert is:

$sql = "INSERT INTO table (field1, field2, field3, almacenes) values ('$value1', '$value2', '$value3', '$almacenes')";

and in the edition still do not checked the selected rows

thank for you reply, look here is my issue

I have this two combogrid, cg2 depends on cg1

Code:

<input class="easyui-combogrid" id="cg1" name="cg1" style="width:230px;" data-options="
	panelWidth:200,
    panelHeight:305,
    idField:'key',
    textField:'name',
    url:'get_category.php',
    mode:'remote',
    fitColumns:'false',
    columns:[[
    	{field:'key',title:'Id',width:60},
        {field:'name',title:'Name',width:175}
    ]],
    onHidePanel: function(){
    	var g = $('#cg1').combogrid('grid');
        var r = g.datagrid('getSelected');
        var key = r.key;
        $('#cg2').combogrid('clear');
        $('#cg2').combogrid('grid').datagrid('load', {
        	param1: $('#other_combo').combogrid('getValue'),
            param2: key
        });
        $('#dg').datagrid('load', { 
            other_combo: $('#other_combo').combogrid('getValue'),
            cg1: key,
            cg2: $('#cg2').combogrid('getValue')
        });
	}" 
/>

<input class="easyui-combogrid" id="cg2" name="cg2" style="width:270px;" data-options="
    panelWidth:500,
    idField:'key',
    textField:'description',
    url:'get_products.php',
    mode:'remote',
    fitColumns:'false',
    columns:[[
            {field:'key',title:'Id',width:100},
            {field:'description',title:'Description',width:140},
            {field:'price',title:'Price',width:60}
    ]],
    queryParams: {
        param1: $('#other_combo').combogrid('getValue'),
        param2: $('#cg1').combogrid('getValue')
    },
    onHidePanel: function(){
        var g = $('#cg2').combogrid('grid');
        var r = g.datagrid('getSelected');
        var key = r.key;
        $('#dg').datagrid('load', { 
            other_combo: $('#other_combo').combogrid('getValue'),
            cg1: $('#cg1').combogrid('getValue'),
            cg2: key
        });
    }" 
/>

When I change a category in cg1 I notice that cg2 change his content ok, for example:

cg1 = garden

cg2 loads the content of products:

-- plantpot
-- shovel
-- fertilizer

then I change it another category:

cg1 = cleaning

cg2 loads the content of products:

-- vacuum cleaner
-- garbage bag
-- trash can

The problem is that having selected cleaning category, I write fertilizer for search and the combogrid show me the result. Looks like the param2 don't be send it in cg2

That's a mistake because fertilizer dont belong it to cleaning category

any idea?

hi everybody

how can I post more variables besides q?

I've already used the queryParams property, and is helpful at te begining, but then I have another combogrid and when I change it updates this combogrid with other variables, the problem comes when I type a word, I think that the combo only sends q no my others variables.

I may think that I should use filter function but I dont know how implement

would appreciate any help

thanks

I'm using the combogrid with multiple property in a form.
I have 2 actions: Add and Edit, so when I do the Add, the combogrid it looks ok but in the php side only got the last item I selected.
To correct this issue I added like a "new" parameter in the onSubmit function for the submit method.
Like this:
param.almacenes = $('#almacenes').combogrid('getValues');
and it works, I've got every item I selected.
But when I want do a edit a register, I select it and I get a message error:

The object does not accept the property or method join.

In this case the combogird should load the values store in the data base in that field and I get a blank combogrid.

Here's my full code:

the html:

the combogrid:

Code:

<input id="almacenes" name="almacenes" class="easyui-combogrid" style="width:240px" 
                            data-options="  
                            multiple: true,
                            panelWidth:240,
                            panelHeight:280,
                            mode:'remote',
                            url: 'folder/get_almacenes.php',
                            idField:'id', //like 100, 300 o A23
                            textField:'id',
                            fitColumns:false,
                            columns:[[
                                    {field:'ck',checkbox:true},
                                    {field:'id',title:'Clave',width:50},
                                    {field:'name',title:'Nombre',width:155}
                                ]]"
                        />

easyui function to save the form data:

Code:

function save(){
	$('#form').form('submit',{
		url: url, 
		onSubmit: function(param){
			param.almacenes = $('#almacenes').combogrid('getValues'); //this instruction had to add to get all the items I select......otherwise I only get the last one select
			var isValid = $(this).form('validate');
			return isValid;
		},
		success: function(result){ 
			var result = eval('('+result+')');
			if (result.success){
				$('#dlg').dialog('close');
				$('#dg').datagrid('reload');
				$.messager.alert('Aviso','Operación éxitosa','info');
			} else{
				$.messager.alert('Error',result.msg,'error');
			}
		}
	});
}

and the php code:

Code:

//get the variable, 
$almacenes = $_POST['almacenes'];
//the content should be like: 100,300,A23 (for example)
//and after do the insert to db

the field that stores this variable is varchar (100)

I'm using the 1.3.2. version

thank you so much

*sorry for my bad english