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Title: 关于easyUI的datagrid修改某列显示值的问题 Post by: ichenkj on September 03, 2014, 07:04:55 PM hi！(Sorry. I will only this one, the other I said Chinese.)
大家好！ 今天我在开发的时候碰到一个问题，就是不知道怎么在不刷新列表的情况修改某一行中某一列的值。 大概的效果是这样的：鼠标选择某行，触发onSelect事件，发送请求给服务器修改状态，返回修改成功的状态标识。前端根据结果修改该行的标题(去掉“【未读】”,把字体设置为不加粗)。 附件的图片有说明要实现的效果。 Title: Re: 关于easyUI的datagrid修改某列显示值的问题 Post by: ichenkj on September 04, 2014, 01:11:22 AM Translate：
Hello everyone. I have a problem in the development of today, but I don't know how to modify the value for a column of a row in the not refresh the list of. General effect is this: the mouse to choose a line, the onSelect event fires, sends a request to the server to modify the state, return to modify the status identification success. The front end is modified according to the result of the line (remove the title "[unread]", the font is not bold). The attached pictures illustrate the effect to be achieved. Title: Re: 关于easyUI的datagrid修改某列显示值的问题 Post by: hjzhbb7758 on September 04, 2014, 03:17:47 AM Translate： Hello everyone. I have a problem in the development of today, but I don't know how to modify the value for a column of a row in the not refresh the list of. General effect is this: the mouse to choose a line, the onSelect event fires, sends a request to the server to modify the state, return to modify the status identification success. The front end is modified according to the result of the line (remove the title "[unread]", the font is not bold). The attached pictures illustrate the effect to be achieved. api datagrid updateRow 试试 Title: Re: 关于easyUI的datagrid修改某列显示值的问题 Post by: ichenkj on September 10, 2014, 08:28:02 AM 谢谢楼上的解答，问题确实是按你的方法解决了。多谢！
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