EasyUI Forum

General Category => EasyUI for jQuery => Topic started by: cp_Burn on May 16, 2013, 12:40:40 PM



Title: Datagrid - How can I display an image in a Cell?
Post by: cp_Burn on May 16, 2013, 12:40:40 PM
Hi there

How can I display an image in a Cell?
I'm using the grid like this example: http://www.jeasyui.com/tutorial/datagrid/datagrid22.php (http://www.jeasyui.com/tutorial/datagrid/datagrid22.php) and the content of grid have been loaded dynamically.

Thanks.


Title: Re: Datagrid - How can I display an image in a Cell?
Post by: 2plus2 on May 16, 2013, 06:30:07 PM
this might be helpful:

http://www.jeasyui.com/tutorial/datagrid/datagrid16.php

Another way might be to use the formatter option. pass in the path and image name, and reformat it as an image tag.


Title: Re: Datagrid - How can I display an image in a Cell?
Post by: cp_Burn on May 17, 2013, 11:29:13 AM
Thanks for reply.

I solved this problem returning in select an string like this: '<img src="myimage.png" />'.