EasyUI Forum

Please help me...
I want to send the link post to  query.

Example  :

  (http://upic.me/i/d6/sample.png) (http://upic.me/show/52754488)


function formatDetail(value,row){
   
      return '<input type="button" id="btn1"  value="ckick_show_detail" onclick="formatDetail_click (' + row.holiday_factory_n_id  + ')">';
   
   }


   
function formatDetail_click (row){
   
       var param = 'holiday_factory_n_id='+row.holiday_factory_n_id;
         $.post('holiday_head_menu.php?' , param
         
         , function (data_mh){
//            alert(data);
            $('#dg_mh').html(data_mh);
         });
   }
   




***********************************************************************************************************


<?php
include 'include/conn.inc.php';


$id_mh = $_REQUEST['id_mh'];
$holiday_factory_n_id = $_REQUEST['holiday_factory_n_id'];


$rs = mssql_query("SELECT     TOP 200 dbo.DW_holiday_date_n.holiday_date_id, dbo.DW_holiday_date_n.holiday_factory_n_id, dbo.DW_holiday_type_n.holiday_type_name,
                      dbo.DW_holiday_date_n.holiday_type_id
FROM         dbo.DW_holiday_date_n INNER JOIN
                      dbo.DW_holiday_type_n ON dbo.DW_holiday_date_n.holiday_type_id = dbo.DW_holiday_type_n.holiday_type_id
WHERE     (DW_holiday_date_n.holiday_factory_n_id = 'holiday_factory_n_id')");
$result = array();
while($row = mssql_fetch_object($rs)){
   
   $row->holiday_date_id = iconv('tis-620','utf-8',$row->holiday_date_id);
   $row->holiday_factory_n_id = iconv('tis-620','utf-8',$row->holiday_factory_n_id);
   $row->holiday_type_name = iconv('tis-620','utf-8',$row->holiday_type_name);
   $row->holiday_type_id = iconv('tis-620','utf-8',$row->holiday_type_id);

   array_push($result, $row);
}
echo json_encode($result);

?>

function formatDetail_click(row){     
      
       var param1 = row;
       alert(param1);
      
       var param = {"holiday_factory_n_id":param1};
       $("#dg_mh").datagrid("load", param);


   }

Please describe your question more clearly.