EasyUI Forum

General Category => EasyUI for jQuery => Topic started by: jaimi on January 20, 2015, 05:29:29 AM



Title: depending pagination display
Post by: jaimi on January 20, 2015, 05:29:29 AM
Hi, I want to control the appearance of the pagination buttons depending on the resultset of the edatagrid.
for example, if the value of result >0 then the button should be inactive or not visible.
How to?

 var PferdPager = $('#edgPferd').datagrid().datagrid('getPager');   
 PferdPager.pagination({
  showPageList: false,
  showRefresh : false,
  displayMsg  : '{from} bis {to} von {total} Pferden'
  // Zum Editieren einschalten !!
 
  ,buttons     :[
   {iconCls:'icon-property',tooltip: 'Detail anzeigen',handler:function(){viewPferd();}}
  ,{iconCls:'icon-add'     ,tooltip: 'Pferd eintragen',handler:function(){addPferd();}}
  ,{iconCls:'icon-edit'    ,tooltip: 'Angaben modifizieren',handler:function(){editPferd();}}
  ]
 }).find('.l-btn').each(function(){
   var opts = $(this).linkbutton('options');
   if (opts.tooltip){
      $(this).tooltip({
         content: opts.tooltip
      })
   }
 });//PferdPager