EasyUI Forum

I have this combogrid:

      $('#cbgridSucursal').combogrid({
         panelWidth: 500,
         panelHeight:250,
         required:true,
         singleSelect:true,
         missingMessage: 'Debe seleccionar una Sucursal.',
         idField: 'Codigo',
         textField: 'DescSuc',
         url: 'Ajax/get_Sucursales.asp?Nom=N',
         method: 'post',
         columns: [[
            {field:'Codigo',title:'Numero',width:40, align:'right'},
            {field:'DescSuc',title:'Nombre',width:120},
            {field:'SucServCodigo',title:'SucServCodigo',width:120},
            {field:'SucServDesc',title:'Servicio',width:150}
         ]],
         fitColumns: true,
         onSelect: function(rec){
            var g = $('#cbgridSucursal').combogrid('grid');   // get datagrid object
            var r = g.datagrid('getSelected');   // get the selected row

            selecting any combogrid row , always SucServCodigo is the first row of the combogrid

            alert('Ajax/get_Sucursales.asp?SucCod='+r.Codigo+'&SucServCod='+r.SucServCodigo);
            
                                Can I get the value of other columns in a combogrid ?
            $.ajax({
               type: 'GET',
               url: 'Ajax/get_Sucursales.asp?SucCod='+r.Codigo+'&SucServCod='+r.SucServCodigo,
               contentType :'charset=ISO-8859-1',
               success: function (result,textStatus, jqXHR) {
                  var DatSucInc = eval(result);
               },
               error: function (req, status, error) {
                  alert("ATENCION: Se produjo un error al buscar los datos de la Sucursal.");
               }
            });
         }
      });
      var grid = $('#cbgridSucursal').combogrid('grid');
      grid.datagrid('enableFilter');

The 'onSelect' event has give you the selected row data, please try this:

My problem is that I had several rows with the same ID . In my combogrid , the unique key was two columns.
Solution : Create a new hidden column as key with two values

Best regardsssss

The id field value must be unique. You have set 'idField' to 'Codigo', you can not load data with duplicate 'Codigo' field values.

thankssssssssss