Show Posts
|
Pages: [1]
|
3
|
General Category / EasyUI for jQuery / Re: Populating data from database to Datagrid with Checkbox
|
on: September 26, 2015, 10:04:25 AM
|
Thanks for reply anda that the solution i have change the sql $sql = "SELECT main_data.itemid AS itemid, offer_data.itemid AS itemid2, main_data.listprice AS listprice, offer_data.unitcost AS unitcost, offer_data.attr AS attr, offer_data.statusId AS statusId FROM main_data LEFT JOIN offer_data ON offer_data.itemid = main_data.itemid";
And the change the JS onLoadSuccess: function(data) { $('#dg').datagrid('getPanel').find('div.datagrid-header input[type=checkbox]').attr('disabled','disabled'); for (var i=0; i<data.rows.length; i++) { if(data.rows[i]['itemid] === data.rows[i]['itemid2']) { $(this).datagrid('checkRow', i); } } },
|
|
|
4
|
General Category / EasyUI for jQuery / Re: Populating data from database to Datagrid with Checkbox
|
on: September 25, 2015, 04:55:04 AM
|
My apologize if my explanation on the top is not clear. so, his is what i mean. I have datatabase name " test" and table " main_data" and " offer_data", with detail is Data on table " main_data" itemid | listprice | EST-1 | 112 | EST-2 | 100 | EST-3 | 98 | EST-4 | 56 | EST-5 | 88 | EST-6 | 121 | EST-7 | 44 | EST-8 | 76 | EST-9 | 56 |
Data on table " offer_data" itemid | unitcost | attr | statusId | EST-1 | 12 | Large | true | EST-6 | 13 | Spotted Adult Female | true | EST-7 | 23 | Green Adult | true | EST-9 | 23 | Adult Female | false |
When i am on edit page, i'll show all data from table main_data to datagrid with data from table offer_data where if main_data.itemid=offer_data.itemid that row automatic checked on loadThis is my script edit.php <table id="dg" class="easyui-datagrid" style="width:600px" url="data/main_data.php" title="Edit Data" iconCls="icon-save" fitColumns="true" idField="itemid"> <thead> <tr> <th field="ck" width="80" checkbox="true">Item ID</th> <th field="itemid" width="80">Item ID</th> <th field="listprice" width="80" align="right">List Price</th> <th field="unitcost" width="80" align="right" data-options="editor:'numberbox'">Unit Cost</th> <th field="attr" width="150" data-options="editor:'textbox'">Attribute</th> <th field="statusId", data-options="align: 'center', editor:{ type:'combobox', options:{ valueField:'statusId', textField:'statusName', panelHeight:'auto', data: [{ statusId: '', statusName: '- Choose -' },{ statusId: 'true', statusName: 'Active' },{ statusId: 'false', statusName: 'Non Active' }] } } " width="80"><b>Status</b></th> </tr> </thead> </table>
main_data.php require_once('config.php');
$sql = "SELECT main_data.itemid AS itemid, main_data.listprice AS listprice, offer_data.unitcost AS unitcost, offer_data.attr AS attr, offer_data.statusId AS statusId FROM main_data LEFT JOIN offer_data ON offer_data.itemid = main_data.itemid";
$result = $conn->query($sql);
$data = array(); while($row = mysqli_fetch_assoc($result)){ $data[] = $row; } echo json_encode($data);
Please someone help me, Thanks
|
|
|
5
|
General Category / EasyUI for jQuery / Populating data from database to Datagrid with Checkbox [Solved]
|
on: September 22, 2015, 10:36:25 PM
|
Now I can save the data from Datagrid with Checkbox, Combobox and Textbox to database. http://www.jeasyui.com/forum/index.php?topic=5248.0My question is: How can i populate data from database to Datagrid and automatic fill the Checkbox, Combobox and Textbox ? Please Help Me, Thanks. This is My Script: HTML <table id="dg" class="easyui-datagrid" style="width:600px;height:250px" url="data/datagrid_data.json" title="Load Data" iconCls="icon-save" fitColumns="true" idField="itemid"> <thead> <tr> <th field="ck" width="80" checkbox="true">Item ID</th> <th field="itemid" width="80">Item ID</th> <th field="productid" width="80">Product ID</th> <th field="listprice" width="80" align="right">List Price</th> <th field="unitcost" width="80" align="right" data-options="editor:'numberbox'">Unit Cost</th> <th field="attr1" width="150" data-options="editor:'textbox'">Attribute</th> <th field="statusName", data-options="align: 'center', editor:{ type:'combobox', options:{ valueField:'statusId', textField:'statusName', panelHeight:'auto', data: [{ statusId: '', statusName: '- Choose -' },{ statusId: 'true', statusName: 'Active' },{ statusId: 'false', statusName: 'Non Active' }] } } " width="80"><b>Status</b></th> </tr> </thead> </table>
Javascript function save() { var rows = []; var dg = $('#dg'); $.map(dg.datagrid('getChecked'), function(row){ var index = dg.datagrid('getRowIndex', row); var editors = dg.datagrid('getEditors', index); if (editors.length){ rows.push({ itemid: row.itemid, unitcost: $(editors[0].target).numberbox('getValue'), attr1: $(editors[1].target).textbox('getValue'), statusName: $(editors[2].target).combobox('getValue') }); } }); $.ajax({ url:'./data.php', type: 'POST', data: {data: JSON.stringify(rows)}, cache: false }); } PHP (getdata.php) $conn = mysqli_connect($host, $user, $pass, $db); mysqli_query($conn, "SELECT * FROM tbl_test");
|
|
|
6
|
General Category / EasyUI for jQuery / Re: Datagrid getChecked data to Array, Post to PHP and Parse
|
on: September 22, 2015, 06:36:15 AM
|
Thank for reply stworthy. Its Works. And this i give the code Javascript function save() { var rows = []; var dg = $('#dg'); $.map(dg.datagrid('getChecked'), function(row){ var index = dg.datagrid('getRowIndex', row); var editors = dg.datagrid('getEditors', index); if (editors.length){ rows.push({ itemid: row.itemid, unitcost: $(editors[0].target).numberbox('getValue'), attr1: $(editors[1].target).textbox('getValue'), statusName: $(editors[2].target).combobox('getValue') }); } }); $.ajax({ url:'./data.php', type: 'POST', data: {data: JSON.stringify(rows)}, cache: false }); }
PHP (data.php) $conn = mysqli_connect($host, $user, $pass, $db); $data = json_decode($_POST['data'], true); mysqli_query($conn, "DELETE * FROM tbl_test"); foreach($data as $dt) { mysqli_query($conn, "INSERT INTO tbl_test (itemid, unitcost, attr1, statusName) VALUES ('$dt[itemid]', '$dt[unitcost]', '$dt[attr1]', '$dt[statusName]')"); } ?>
I think is the good way, if i wrong please correct.
|
|
|
7
|
General Category / EasyUI for jQuery / Datagrid getChecked data to Array, Post to PHP and Parse [Solved]
|
on: September 19, 2015, 02:31:16 AM
|
Hello All, I have a problem with datagrid (not edatagrid) inline row editing, i try to modification easyui datagrid tutorial http://www.jeasyui.com/tutorial/datagrid/datagrid3.phpMy question is: 1. how can i get all checked row to array including numberbox, textbox and combobox value ? 2. post them to PHP ? 3. Parse the array ini PHP, so i can insert them to Database. Please Help Me, Thanks. HTML <table id="dg" class="easyui-datagrid" style="width:600px;height:250px" url="data/datagrid_data.json" title="Load Data" iconCls="icon-save" fitColumns="true" idField="itemid"> <thead> <tr> <th field="ck" width="80" checkbox="true">Item ID</th> <th field="itemid" width="80">Item ID</th> <th field="productid" width="80">Product ID</th> <th field="listprice" width="80" align="right">List Price</th> <th field="unitcost" width="80" align="right" data-options="editor:'numberbox'">Unit Cost</th> <th field="attr1" width="150" data-options="editor:'textbox'">Attribute</th> <th field="statusName", data-options="align: 'center', editor:{ type:'combobox', options:{ valueField:'statusId', textField:'statusName', panelHeight:'auto', data: [{ statusId: '', statusName: '- Choose -' },{ statusId: 'true', statusName: 'Active' },{ statusId: 'false', statusName: 'Non Active' }] } } " width="80"><b>Status</b></th> </tr> </thead> </table>
Javascript <script> function save() { var ids = []; var rows = $('#dg').datagrid('getSelections'); for(var i=0; i<rows.length; i++){ ids.push(rows[i].itemid); } alert(ids.join('\n')); } $(document).ready(function () { var lastIndex; $('#dg').datagrid({ onLoadSuccess: function(data) { $('#dg').datagrid('getPanel').find('div.datagrid-header input[type=checkbox]').attr('disabled','disabled'); }, onCheck: function(index,row){ if(lastIndex != index) { $(this).datagrid('beginEdit', index); } }, onUncheck: function(index,row){ if(lastIndex != index) { $(this).datagrid('endEdit', index); } }, }); }); </script>
|
|
|
|