Good morning,
I tried the example and I understand why I can't solve with my code. The example works in Firefox, IExplorer, but in Chrome it doesn't display the alert.

Thank you for your suggestion.
I downloaded version 1.9.3, but the onBeforeSelectPage event handler seems not to be handled.
Below the code that I tested that does not display the alert.

....
....
var pager = dd.datagrid('getPager');
var popts = pager.pagination('options');
var onBeforeSelectPage = popts.onBeforeSelectPage;

popts.onBeforeSelectPage = function(pageNumber, pageSize){
      alert('ok');
      return false;
}

Thanks for the reply.
I solved the problem this way (see code below)
but I would have preferred to block the event: onSelectPage. It can be done ?

Michele.

...
...
var pager = dd.datagrid('getPager');
var popts = pager.pagination('options');
var onSelectPage = popts.onSelectPage;
popts.onSelectPage = function(pageNumber, pageSize){
      
    var rows = $('#tt').datagrid('getChanges');
    alert(rows.length+' rows are changed!');
    if(rows.length > 0)
    {
          var rc = confirm('Ci sono records da salvare. Confermi ?');
          if(rc)
          {
            var dataString = JSON.stringify(rows) ;
            var url = 'save.php';
            $.ajax(url, {
                type:'POST',
                data: {myData: dataString},
                   success: function(data){
                alert($.trim(data) );
                   },
                   error: function(){
                  alert('Errore');
                   }
            });
            }         
          onSelectPage.call(this, pageNumber, pageSize);

      }   
      else
      {
          onSelectPage.call(this, pageNumber, pageSize);
      }                                 

Hello, sorry if I use an automatic translator, but I don't speak English well.
I would need to stop paging when there is still data to save in datagrid remote.
Is it possible to stop the event and stay on the modified data page?
Thank you.

Thank you
Stworthy, I seem to have realized I forgot to put: .... options: {precision: 2, decimalSeparator: ','}, ... in filter definition. Now the error has disappeared.
Greetings.

Michele.

Good morning at all, I entered a ticket a few days ago.

https://www.jeasyui.com/forum/index.php?topic=6706.0

There is no solution.
 
Unfortunately I have not been able to solve this problem yet.

I add an application screen with the error console.


Thank you all.

Michele.

Good evening, I'm using the example found in the demo that works fine, but when typing something in the filter: listprice or unitcost, a console error is sent even if the video response is correct.

datagrid-filter.js:480 Uncaught TypeError: Cannot read property 'target' of null
    at addFilterRule (datagrid-filter.js:480)
    at HTMLDivElement.<anonymous> (datagrid-filter.js:1012)
    at Function.each (jquery.min.js:2)
    at m.fn.init.each (jquery.min.js:2)
    at Object.addFilterRule (datagrid-filter.js:1011)
    at m.fn.init.$.fn.datagrid (jquery.easyui.min.js:10648)
    at _doFilter (datagrid-filter.js:268)
    at datagrid-filter.js:259


Why ?
Attached all the code I'm using.
Thank you for your response.

Michele.

Good morning, I have a little problem. I defined a datagrid with the property view: detailView, when I open another datagrid where I do not need detailView, I still see it active.

see Annex (loadAziende (), loadParticelle (), loadProdotti ()

How can I forgive view: default?

Michele.

Thank you.
This time it works fine.

Greetings.
Lo Monaco Michele.

Good morning, I tried to insert the recommended code, but still dominates the event: doFilter default. see Attachment.

Thank you.
Michele.

Thanks, now I try and let you know.
Michele.

Good evening, I apologize for my poor English, use a translator.
I defined a combobox with a remote datasource, but when I type something in the input box called the server to each character by slowing down the operation.
You can call the server unless I have written at least 3-4 characters?

my code attached.

Thank you.