pass current selected record data in a grid to another php file

[wel]

I use inline grid and I need to pass all the fields values of the current selected record to another php file and same time navigate to this page so I can read values like this:

$myvar = $_REQUEST['field'];

So I added new button on the grid tool bar like this:

Code:

<a href="#" class="easyui-linkbutton" iconCls="icon-more" plain="true" onclick="getSelected()">Detail Page</a>

And the script was like this

Code:

<script type="text/javascript">
    function getSelected(){
        var row = $('#dg').datagrid('getSelected');
        if (row){
            window.location = 'job_detail.php?jd='+row.job_message_id;
</script>

I dont want to pass about 15 fields in a GET way so is there a way to POST all values to job_detail.php page ?

[wel]

I can read the id and then select from the db all fields again but I was wondering if datagrid can pass the row object with all values to another php page or not ?.

[jarry]

Please try this code to post the selected row to your server.

Code:

var row = $('#dg').datagrid('getSelected');
if (row){
	$.post(url, row, fucntion(){
		//...
	})	
}

[wel]

Thanks I tried JQuery post and it really post row to another php page (ex detail.php) but the problem I still stay at the grid page I need to also to move to this new page detail.php to simply display the grid current selected record in a form style, any idea ?

[jarry]

You can't send a post to server by using 'location.href'.

[wel]

Is there any method to send row object to detail.php page and also move to this page ?

[wel]

I found a way , I used cookies and then read the data using json_decode.