datagrid hyperlink event

[kvkv]

Hi I used easyUI datagrid to view the user details. User has 10 attributes. I need to show only 6(columns)  attributes in the datagrid. I want to add new column as "View Details". I need to display the 10 user details in another page as user_details.php when I click the viewdetails hyper link at any row. I retrieved data from get_details.php page.

I attached code which I used in the project below

//datagrid page
<table id="dg" title=" Requests" class="easyui-datagrid" style="width:850px;height:330px"
         url="/get_details.php"
         toolbar="#toolbar" pagination="true"
         rownumbers="true"  singleSelect="true">
      <thead >
         <tr>

                            <th field = "name" width = "120">Name</th>
                            <th field = "address" width = "120">Address</th>
                            <th field = "phone" width = "120">Phone</th>
                            <th field = "expected_time_period" width = "120">Expect Time</th>
                            <th field ='' " width = "120">View Details</th>
                           
         </tr>
      </thead>
   </table>
//In the datagrid I attached View Details column. But I dont know how give the hyper link event to the column.All the columns get values from get_details.php page except this column. I need to send user Id throw the hyperlink to user_details.php. So please suggestion to the line "<th field ='' " width = "120">View Details</th>"

//get_details.php
<?php
   $page = isset($_POST['page']) ? intval($_POST['page']) : 1;
   $rows = isset($_POST['rows']) ? intval($_POST['rows']) : 10;
   $offset = ($page-1)*$rows;
   $result = array();
       

       
        $rs = mysql_query("select count(*) from user where  status = 1");
   $row = mysql_fetch_row($rs);
   $result["total"] = $row[0];
   $rs = mysql_query("select * from user where  status = 1 limit $offset,$rows");
   
   $items = array();
   while($row = mysql_fetch_object($rs)){
      array_push($items, $row);
   }
   $result["rows"] = $items;
//print_r($Items);
   echo json_encode($result);

?> 
 I am new to php coding. I also attached screen shot of the datagrid. Please check it.

Thanks & Regards

[stworthy]

Please use 'formatter' function to define a hyperlink column.

Code:

<script>
	function formatDetail(value,row){
		var href = 'get_details.php?userid='+row.id;
		return '<a target="_blank" href="' + href + '">View Detail</a>';
	}
</script>
<th field ="detail" width = "120" formatter="formatDetail">View Details</th>

[kvkv]

Hi stworthy,

Thank you very much. It works fine.

Thanks & Regards